\(\left\{\begin{matrix}\sum_{j=1}^{K}{\lambda_{j}\left(u_{\alpha}\right)\bullet\overline{C}\left(u_{i},u_{j}\right)+\mu(u_{\alpha})}=\overline{C}\left(u_{i},u_{\alpha}\right),\ i=1,\cdots,K\\ \sum_{j=1}^{K}{\lambda_{j}\left(u_{\alpha}\right)}=1\\ \end{matrix}\right.\ \), (4)